Question

if x=-1/2 is a zero polynomial p (x)=8xcube-axsquare-x+2,find the value of a​

Answer 1

Answer:

a = 6

Step-by-step explanation:

p(x) = 8x^3-ax^2-x+2

p(-1/2) = 8*(-1/2)^3-a*(-1/2)^2-(-1/2)+2 = 0

             8*(-1/8)-a*(1/4)+1/2+2=0

            -1-a/4+1/2+2 = 0

             1+1/2-a/4 = 0

             (4+2-a) / 4 = 0

             6-a = 0

            -a = -6

             a = 6

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Answer 2

Answer:

$\mathbb{GIVEN}$

$\tt{\frac{(-1)}{2} }$ is a factor of p(x)

$\tt{8x^{3} - ax^{2} - x + 2 = 0}$

When we put the value of x as $\tt{\frac{(-1)}{2}}$ :

=》 $\tt{-4 - a + 2 + 8 = 0}$

=》 a = 6