Question

If x= 1/2 is the zero of the polynomial 2x^2 + Kx-12. Find the value of K

Answer 1

Heya,

If x = 1/2 is the  zero of the polynomial 2x^2 + Kx-12 then,

p(1/2) = 0

⇒ 2(1/2)² + k (1/2) - 12 = 0

⇒1/2 + k/2 -12 = 0

⇒1+ k -24/2 = 0

⇒ k -23 = 0

⇒ k = 23

Hope it helps u.......

Answer 2

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8.

$\large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }$

Hence, the value of ‘k’ is founded .