if x=-1/2 is zero of p(x) =8x ^3-k find the value of k
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p( - 1 /2 ) = 8 ( -1 /2 ) ^3 - k
0 = 8 * (-1 / 8 ) - k
0 = -1 - k
- k = 1
k = -1 Ans .
0 = 8 * (-1 / 8 ) - k
0 = -1 - k
- k = 1
k = -1 Ans .
VijayaLaxmiMehra1:
its wrong dear
Answered by
4
Hey!!
Here,
X = - 1 / 2 is a zero of P ( X ) = 8X^3 - k
P ( X) = 8X^3 - k
P (- 1 / 2) = 8 ( - 1 / 2 )^3 - k
=> 0 = 8 ( -1 / 8) - k
=> 0 = - 8/8 - k
=> 0 = - 1 - k
=> k = - 1.
_______________________
Hope it will helps you:-)
Here,
X = - 1 / 2 is a zero of P ( X ) = 8X^3 - k
P ( X) = 8X^3 - k
P (- 1 / 2) = 8 ( - 1 / 2 )^3 - k
=> 0 = 8 ( -1 / 8) - k
=> 0 = - 8/8 - k
=> 0 = - 1 - k
=> k = - 1.
_______________________
Hope it will helps you:-)
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