if x=1/(2 root3) is a zero of the polynomial p(x)=2kX^2-7x+k,then find value of k..
please answer please....
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x=1/2√3 is a zero of the polynomial,
so P(1/2√3)=0
⇒2k(1/2√3)²-7/2√3+k=0
⇒k/6-7/2√3+k=0
⇒7k/6=7/2√3
⇒k=√3.
so P(1/2√3)=0
⇒2k(1/2√3)²-7/2√3+k=0
⇒k/6-7/2√3+k=0
⇒7k/6=7/2√3
⇒k=√3.
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