Question

If x = 1+ √2 ,
then find { ϰ + 1ϰ }²​

Answer 1

Answer:

4(3+2√2)

Step-by-step explanation:

(X+1X)^2= (1+√2+1+√2)^2

= (2+2√2)^2

= 2^2+(2√2)^2+2.2.2√2

=4+8+8√2

=12+8√2

=4(3+2√2)

hope it helps :)

Answer 2

Step-by-step explanation:

x = 1+ √2

{ x + 1x}²

{ ( 1+√2 ) + ( 1 (1+√2) ) }²

{ (1+√2) + ( 1 + √2) }²

(1+√2)² + (1+√2)² + 2 ( 1+√2) (1+√2)

(1+2) + (1+2) + 2+√8 × 1+√2

3+3+2+√8×1+√2

8+√8×1+2

8+√8+2