if x = 1 + √2 ,then find the value of (x + 1x )^2
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Step-by-step explanation:
Given = x = 1 + √2
so (x+1x)²
(2x)²
[2(1+√2)]²
(2+2√2)²
2²+(2√2)²+2*2*2√2
4+8+8√2
value of (x+1x) = 12+8√2
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