Math, asked by msrathoremadro, 2 months ago

if x = 1 + √2 ,then find the value of (x + 1x )^2​

Answers

Answered by pushkardigraskar2005
2

Answer:

Here's your answer

Step-by-step explanation:

Given = x = 1 + √2

so (x+1x)²

(2x)²

[2(1+√2)]²

(2+2√2)²

2²+(2√2)²+2*2*2√2

4+8+8√2

value of (x+1x) = 12+8√2

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