If x= 1+?2, what is (x-1/x)?
lekhahasa:
is it square root in place of questio mark
Answers
Answered by
1
x=1+√2
1/x=1/(1+√2)
=(1-√2)/[(1+√2)(1-√2)]
=(1-√2)/-1
=√2-1
(x-1/x)=(1+√2)-(√2-1)
=1+√2-√2+1
=2
1/x=1/(1+√2)
=(1-√2)/[(1+√2)(1-√2)]
=(1-√2)/-1
=√2-1
(x-1/x)=(1+√2)-(√2-1)
=1+√2-√2+1
=2
Answered by
1
1+√2 −1−√2/1−√2²
⇒1+√2−1−√2/1−2
⇒1 + √2 - 1 - √2/-1
⇒1 + √2 + 1 - √2
⇒1 + 1
⇒2
⇒1+√2−1−√2/1−2
⇒1 + √2 - 1 - √2/-1
⇒1 + √2 + 1 - √2
⇒1 + 1
⇒2
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