Question

If (x+1)2+(y+1) 2=0 then value of x and y and how?
please answer my question quickly! I mark him/her brainlist!
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Answer 1

Answer:

The answer is $x=-1,y=-1$

Step-by-step explanation:

Given $(x+1)^2+(y+1)^2=0$

We know that square of any real number cannot be negative

$\Rightarrow (x+1)^2\ge 0$ and $(y+1)^2\ge 0$

But their sum is zero $\Rightarrow (x+1)^2=0$ and $(y+1)^2=0$

                                  $\Rightarrow x=-1$ and $y=-1$