Question

if (x-1)^2+(y-1)^2=0 then x^2+y^2=?​

Answer 1

x

2

+y

2

+

x

2

1

+

y

2

1

=4

⇒x

2

+y

2

+

x

2

1

+

y

2

1

−4=0

x

2

+

x

2

1

+y

2

+

y

2

1

−2−2=0

⇒(x

2

+

x

2

1

−2)+(y

2

+

y

2

1

−2)=0

(x−

x

1

)

2

+(y−

y

1

)

2

=0

⇒(x−

x

1

)=0 & (y−

y

1

)=0 ( Since (x−

x

1

)

2

& (y−

y

1

)

2

(both must be greater than or equal to zero )

⇒x=

x

1

& y=

y

1

⇒x

2

=1 & y

2

=1

⇒x

2

+y

2

=1+1=2.

Hence, the answer is 2.

Step-by-step explanation:

Hope you understand it