Question

if (x-1)²+(y-1)²+(z-7)²=0 so what is x²+y²+z²​

Answer 1

Answer:

51

Step-by-step explanation:

the square can never be negative so we can say that

in the equation (x-1)²+(y-1)²+(z-7)²=0

(x-1)²=(y-1)²=(z-7)²=0

then we can find the value of x,y,z which will be 1,1,7

after that 1^2 + 1^2 + 7^2 = 49+1+1 = 51