if x=1/2 y=1/3 z=1/4 then find the value of x(x+y)+y(y+z)
Answers
Answered by
2
Answer:
22/36
x(x+y)+y(y+z)
=1/2(1/2+1/3)+1/3(1/3+1/4)
=1/2(5/6)+1/3(7/12)
=5/12+7/36
=15/36+7/36=22/36
Answered by
0
Answer:
=1/2(1/2+1/3)+1/3(1/3+1/4)
=1/2(3+2/6)+1/3(4+3/12)
=1/2(5/6)+1/3(7/12)
=5/2+7/36
=15+7/36
=22/36
=11/18
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