Math, asked by prathamsinghps4, 6 months ago

if x=1/2 y=1/3 z=1/4 then find the value of x(x+y)+y(y+z)​

Answers

Answered by harsh1234587
2

Answer:

22/36

x(x+y)+y(y+z)

=1/2(1/2+1/3)+1/3(1/3+1/4)

=1/2(5/6)+1/3(7/12)

=5/12+7/36

=15/36+7/36=22/36

Answered by lucky123421
0

Answer:

=1/2(1/2+1/3)+1/3(1/3+1/4)

=1/2(3+2/6)+1/3(4+3/12)

=1/2(5/6)+1/3(7/12)

=5/2+7/36

=15+7/36

=22/36

=11/18

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