Question

If x = - 1/2, y = 1/4 and z = 0, find the value of the following:(i) 8z + 2x – y(ii) z – y + 3x

Answer 1

Answer:

i) - 3/4

Step-by-step explanation:

8z+2-y

8(0)+2(-1/2)-1/4

0+(-2/4)-1/4

= -3/4

Answer 2

Given: x = $-\frac{1}{2}$

           y = $\frac{1}{4}$

           z = 0

To Find: i) 8z + 2x - y (Let it be equation 1)

              ii) z - y + 3x  (Let it be equation 2)

Solution:

i) Substituting the values of x, y, and z in equation 1,

8(0) + 2($-\frac{1}{2}$) - $\frac{1}{4}$

= 0 -1 - $\frac{1}{4}$

= - ( 1 + $\frac{1}{4}$ )

= - ($\frac{4+1}{4}$)

= $-\frac{5}{4}$

= $-1\frac{1}{4}$

Answer: $-1\frac{1}{4}$

ii) Substituting the values of x, y, and z in equation 2,

0 - $\frac{1}{4}$ + 3($-\frac{1}{2}$)

= $-\frac{1}{4} -\frac{3}{2}$

= $-(\frac{1}{4} +\frac{3}{2} )$

L.C.M of 2 and  4 = 4

∴ $- (\frac{1+6}{4} )$

= $-\frac{7}{4}$

= $-1\frac{3}{4}$

Answer: $-1\frac{3}{4}$