Math, asked by aaradhyagupta1, 16 days ago

If x = –1/2, y = 1/4 and z = 0, find the value of the given expressions.
(a) 8z + 2x -y
(b) z – y + 3x​

Answers

Answered by rutujajagtap04
6

Answer:

The value of the given expressions is:

a) -3/4

b) -7/4

Step-by-step explanation:

given,

x= -1/2; y= 1/4; z=0

a) 8z + 2x -y

substituting the values of x, y and z,

8 (0) + 2(-1/4) - 1/4

the multiplication rule for numbers with different sign is,

(+)(-)=(-)

0+ (-1/2) -1/4

-1/2-1/4

the LCM of 2 and 4 is 4

multiplying and dividing -1/2 by 2,

\frac{-1X2}{2X2} -\frac{1}{4}

\frac{-2}{4} - \frac{1}{4}

\frac{-2-1}{4}

\frac{-3}{4}

b) z-y +3x

substituting the values of x, y and z,

0-1/4 + 3(-1/2)

-1/4+(-3/2)

-1/4 - 3/2

the LCM of 2 and 4 is 4

multiplying and dividing 3/2 by 2

\frac{-1}{4} -\frac{3X2}{2X2}

\frac{-1}{4} - \frac{6}{4}

\frac{-1-6}{4}

\frac{-7}{4}

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