Question

if (x-1)^2 +(y-2)^2 +(z-3)^2 =0 then x +y: y+z=? Plz answer me fast​

Answer 1

Answer:

3 : 5

Step-by-step explanation:

Square on any real number can never be 0 or less than 0 till that number itself is 0.

  So, here, if

(x - 1 )^2 + ( y - 2 )^2 + ( z - 3 )^3 is equal to 0 it means all of its terms are 0.

Hence,

      x - 1 = 0   ⇒ x = 1

      y - 2 = 0  ⇒ y = 2

      z - 3 = 0  ⇒ z = 3

Hence,

x + y = 1 + 2 = 3

y + z = 2 + 3 = 5

Answer 2

Solution:-

Square of any number(except complex) is always positive,,,

if all the three terms will be positive then their sqaure can't be equal to 0

But,if this case is given then all the three terms have to be 0,as it will satisfy the given condition

so,

(x-1)^2=0 x=>1

(y-2)^2=0 y=>2

(z-3)^2=0 z=>3

from this value we can find

x+y=3

y+z=5

their ratio{(x+y)/(y+z)}=3/5