Question

if (x-1)^2+(y-3)^2+(z-5)^2+(t-7)^2=0 then xyzt+16is equal to

Answer 1

Answer:

When the parametr squared we are sure about that it is positive , all of parametrs are squared and the result is zero  , as a result , each one is zero therfore :

$(x-1)^{2}=0\\(y-3)^{2}=0\\ (z-5)^{2}=0\\ (t-7)^{2}=0\\  x=1, y=3, z=5, t=7\\ xyzt+16=1*3*5*7+16=121$

Step-by-step explanation: