Math, asked by andersonjerin128, 11 months ago

If X= 1 + 21 / 2 and Y=1 - 21 / 2 then X2 + y2 i?

Answers

Answered by sonalityagi07
0

Answer:

x = 1 + 21/2  and y = 1- 21/2

to find x^2 + y^2

= [x + y]^2 -  2xy

A/Q

={1+21/2 + 1 - 21/2 ]^2 - 2 [1 + 21/2] [1 - 21/2]           [(A-B)(A+B)]

[2] - 2[ ( 1 )^2 - (21/2)^2]                                   [A^2 - B^2]

2 - 2 [ 1 -  441/4 ]

2[ 1 - 1 + 441/4]

2 [ 441/4]

=441 /2

HENCE THE VALUE OF X^2 +Y^2 IS 441/2

Step-by-step explanation:

Answered by vikashkumar08797
6

Answer:

Step-by-step explanation:

x2+y2= (1+2^1/2)^2+ (1-2^1/2)^2

= (a+b)^2+(a-b)^2

so, we get

1+2+2*2^1/2+1+2-2^1/2

1+2+1+2=6 ans.

Similar questions