If X= 1 + 21 / 2 and Y=1 - 21 / 2 then X2 + y2 i?
Answers
Answered by
0
Answer:
x = 1 + 21/2 and y = 1- 21/2
to find x^2 + y^2
= [x + y]^2 - 2xy
A/Q
={1+21/2 + 1 - 21/2 ]^2 - 2 [1 + 21/2] [1 - 21/2] [(A-B)(A+B)]
[2] - 2[ ( 1 )^2 - (21/2)^2] [A^2 - B^2]
2 - 2 [ 1 - 441/4 ]
2[ 1 - 1 + 441/4]
2 [ 441/4]
=441 /2
HENCE THE VALUE OF X^2 +Y^2 IS 441/2
Step-by-step explanation:
Answered by
6
Answer:
Step-by-step explanation:
x2+y2= (1+2^1/2)^2+ (1-2^1/2)^2
= (a+b)^2+(a-b)^2
so, we get
1+2+2*2^1/2+1+2-2^1/2
1+2+1+2=6 ans.
Similar questions