if x=1/2root7, then find the value of x^2-x/2root7
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Answered by
1
x + 1 x = 7
⇒ (x + 1 x )2 =(7)2
⇒ (x2+ 1 x 2 + 2) = 49
⇒ x2+ 1 x 2 = 47
Therefore, x2+ 1 x 2 = 47.
⇒ (x + 1 x )2 =(7)2
⇒ (x2+ 1 x 2 + 2) = 49
⇒ x2+ 1 x 2 = 47
Therefore, x2+ 1 x 2 = 47.
Meghnathakur:
Its not crrct
Answered by
1
If x = 1/2root7-----------{eq1}
Then x^2 = (1/2root7)^2
= 1/28---------eq2
Then .. we divide the eq1 by 2root 7
=> x / (2root7) = ( 1/2root 7 ) ÷ 2root 7
=> x/ 2root 7 = 1/28 -----------eq3
A.T.Q
From eq 2 and 3
1/28 - 1/28
= 0
Then x^2 = (1/2root7)^2
= 1/28---------eq2
Then .. we divide the eq1 by 2root 7
=> x / (2root7) = ( 1/2root 7 ) ÷ 2root 7
=> x/ 2root 7 = 1/28 -----------eq3
A.T.Q
From eq 2 and 3
1/28 - 1/28
= 0
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