If (x-1/2x)=3 find the value of
a)x^2+1/4x^2
b)x^4+1/16x^4
Answers
Answered by
0
Step-by-step explanation:
hello this is your answer
Attachments:
Answered by
0
Answer:
x-1/2x=3
a) x^2+1/4x^2
=(x)^2+(1/2x)^2
=(x-1/2x)^2+2.x.1/2x
=(3)^2+1
=9+1
=10
b) x^4+1/16x^4
=(x^2)^2+(1/4x^2)^2
=(x^2+1/4x^2)^2-2.x^2.1/4x^2
=(10)^2-1/2
=100-1/2
=99 1/2
Similar questions