Math, asked by varshini236, 2 months ago

If (x-1/2x)=3 find the value of
a)x^2+1/4x^2
b)x^4+1/16x^4​

Answers

Answered by karteekpuri99
0

Step-by-step explanation:

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Answered by bagkakali
0

Answer:

x-1/2x=3

a) x^2+1/4x^2

=(x)^2+(1/2x)^2

=(x-1/2x)^2+2.x.1/2x

=(3)^2+1

=9+1

=10

b) x^4+1/16x^4

=(x^2)^2+(1/4x^2)^2

=(x^2+1/4x^2)^2-2.x^2.1/4x^2

=(10)^2-1/2

=100-1/2

=99 1/2

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