Question

if ( x - 1/2x ) = 3 , find the value of
( x^4 + 1/16x^4 )

Answer 1

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Answer 2

Answer:

$(x-\frac{1}{2x})=3$

$(x-\frac{1}{2x})^2=3^2$

$x^2+\frac{1}{4x^2} -1=9$

$x^2+\frac{1}{4x^2} =10$

$(x^2+\frac{1}{4x^2})^2=10^2$

$x^4+\frac{1}{16x^4} +\frac{1}{2} =100$

$x^4+\frac{1}{16x^4} =100-\frac{1}{2}$

$x^4+\frac{1}{16x^4} =\frac{199}{2}=99.5$