Question

If x+1/2x=3 then find the value of x^2+1/4x^2

Answer 1

Answer :

$x + \frac{1}{2x} = 3 \\ \\ \bf on \: squaring \: both \: sides : \\ \\ (x + \frac{1}{2x} ) {}^{2} = (3) {}^{2} \\ \\ x {}^{2} + \frac{1}{4x {}^{2} } + \cancel 2 \times \cancel x \times \frac{1}{ \cancel {2x}} = 9 \\ \\ x {}^{2} + \frac{1}{4x {}^{2} } + 1 = 9 \\ \\ x {}^{2} + \frac{1}{4x {}^{2} } = 9 - 1 \\ \\ \boxed{ \bf x {}^{2} + \frac{1}{4x {}^{2} } = 8}$

Answer 2

HeRe Is Your Ans

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$x + \frac{1}{2x} = 3 \\ \\ squaring \: on \: both \: side \\ \\ {(x + \frac{1}{2x} )}^{2} = {(3)}^{2} \\ \\ {x}^{2} + { (\frac{1}{2x}) }^{2} + 2 \times x \times \frac{1}{2x} \\ \\ {x}^{2} + \frac{1}{4 {x}^{2} } = 8$

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