Math, asked by dishantsharma69, 9 hours ago

if (x)= 1-2x x<= 1 ,
x-1 x>1
evaluate f(0)+f(2).​

Answers

Answered by prajukta1414
0

Answer:

f(x)=

e

1/x

+1

e

1/x

−1

f(x)

x→0

=lim

h→0

e

−1/h

+1

e

−1/h

−1

f(x)

x→0

=lim

h→0

e

1/h

1

+1

e

1/h

1

−1

=

0+1

0−1

=−1

f(x)

x→0

+

=lim

h→0

e

1/h

+1

e

1/h

−1

f(x)

x→0

+

=lim

h→0

1−

e

1/h

1

1−

e

1/h

1

=

1+0

1−0

=1

f(x)

x→0

=f(x)

x→0

+

L.H.L is not equal to R.H.L at x=0.

So, function is not continuous at x=0.

Answered by sahildudhal
1

Answer:

ye 60 tha

Step-by-step explanation:

hope it helps you

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