if x=1/3-2√2 and y= 1/3+2√2 then find x+y + xy
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Answer:
Step-by-step explanation:
x+y = 1/3-2√2 + 1/3+2√2
x+y = 1/3+1/3
x+y = 2/3
now xy = 1/3-2√2 × 1/3+2√2
from (a-b)(a+b) = a^2-b^2
xy = (1/3)^2 - (2√2)^2
xy = 1/9 - 8
xy = -71/9
therefore,
x+y + xy = 2/3 + -71/9
x+y + xy = 2/3 - 71/9
x+y + xy = (6-71)/9
x+y + xy = -65/9
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