If x = 1/3+2√2, then find the value of x - 1/x.
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- Let p (x) = x + 1 / x = 2
- Let p (x) = x + 1 / x = 2= x + 1 = 2x
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.
- Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.You can also make it this way
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