If x=1/3-2√2,then find the value of x^3+4x^2-11x+7
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x=12−3–√
Rationalising gives-
x=2+3–√
x−2=3–√
(x−2)2=3–√2
x2−4x+4=3
x2−4x+1=0
Now, in our expression:
x3−2x2−7x+10
=x3−4x2+2x2−7x+10
=x3−4x2+x−x+2x2−7x+10
=x(x2−4x+1)+2x2−8x+10
=x(0)+2(x2−4x+5)
=2(x2−4x+1+4)
=2(0+4)
=8
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