Question

if x=1/3+2 root 2,then the value of x-1/x is
​

Answer 1

Answer:

((7x)-(1/Vx))^2=x+(1/x)-2*x*(1/x).l.e

(a-b)^2=a*a+b*b-2*a*b.

((7x)-(1/1x))^2=(3-2/2)+(1/3-2/2)-2*(3-

272)*(1/3-2/2).

Rationalising the above factor (3-2V2) 1.e

Multiplying with (3+272) in numerator and

denominator.so the result be (3+212).

((7x)-(1/7x))^2=(3-212)+(3+272)-2.

((vx)-(1/x))^2=3+3–2=4.

Applying square root on both sides

(7x)-(1/7x)=2.

So the answer is 2.