Math, asked by tesla99643, 4 months ago

if x=1/3-2root 2 and y=1/3+2root 2 then value of x^2y+xy^2+xy

Answers

Answered by Anonymous
0

Answer:

ANSWER

x=3+2

2

x

1

=

3+2

2

1

×

3−2

2

3−2

2

=3−2

2

(

x

2

1

)

2

=x+

x

1

−2

=3+2

2

+3−2

2

−2=4

So,

x

x

1

=

4

=±12 Ans

Answered by rahul42291
0

x+y+xy = 7

This is the answer

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