if x=1/3-2root 2 and y=1/3+2root 2 then value of x^2y+xy^2+xy
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Answered by
0
Answer:
ANSWER
x=3+2
2
x
1
=
3+2
2
1
×
3−2
2
3−2
2
=3−2
2
(
x
−
2
1
)
2
=x+
x
1
−2
=3+2
2
+3−2
2
−2=4
So,
x
−
x
1
=
4
=±12 Ans
Answered by
0
x+y+xy = 7
This is the answer
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