Math, asked by kishanaggarwal51, 11 months ago

if x=(-1/3)^-3÷(2/3)^-4,find the value of (x/y+y/x)^-1​

Answers

Answered by sanjeevk28012
0

Answer:

The value of expression [\frac{x}{y} + \frac{y}{x}]^{-1}  is \dfrac{73}{36}  .

Step-by-step explanation:

Given as :

\dfrac{x}{y}   = \dfrac{(\frac{-1}{3})^{-3}}{(\frac{2}{3})^{-4}}

Or, \dfrac{x}{y} = \dfrac{-27}{\frac{81}{8}}

Or, \dfrac{x}{y} = \dfrac{-24}{9}                  ......A

So The value of given expression  [\frac{x}{y} + \frac{y}{x}]^{-1}

Or, [\frac{x^{2}+y^{2}}{xy} ]^{-1}

or, [\dfrac{xy}{x^{2}+y^{2}} ]^{1}

Or, \dfrac{y}{x} + \dfrac{x}{y}

Or,  \dfrac{-9}{24} - \dfrac{24}{9}

Or, \dfrac{-81-576}{216}

Or, \dfrac{657}{216}

Or, \dfrac{73}{36}

Hence, The value of expression [\frac{x}{y} + \frac{y}{x}]^{-1}  is \dfrac{73}{36}  . Answer

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