Question

If x= 1/(3-√8) and y= 1/( 3 +√8) then the value of (x +y)2

Answer 1

Answer:

- y=3-√8 x² =(3+√8)²= 3²+2*3*√8+(√8)² = 9+6√8+8 =17+6√8 y²=(3-√8)²=3²+(√8)²-2*3*√8 = 9+8-6√8 = 17-6√8 1/x²+1/y² = 1/(17+6√8

Step-by-step explanation:

hope that helped