Question

if (x-1)³=8 then the value of (x+1)² is​

Answer 1

Answer:

The value of [x+1]^{2}[x+1]

2

is 16

Given:

[x-1]^{3}=8[x−1]

3

=8

To find:

[x+1]^{2}[x+1]

2

Solution:

To find the value of x,

[x-1]^{3}=8[x−1]

3

=8

[x-1]=(8)^{\frac{1}{3}}[x−1]=(8)

3

1

[x-1]=2[x−1]=2

x=3x=3

Then, [x+1]^{2}[x+1]

2

is,

[x+1]=3+1[x+1]=3+1

[x+1]=4[x+1]=4

[x+1]^{2} \Rightarrow 4^{2}[x+1]

2

⇒4

2

[x+1]^{2}=16[x+1]

2

=16

Any polynomial with a degree of two is called as a quadratic polynomial. Such types of equations involving quadratic polynomials were called as quadratic equations.

Similarly, a polynomial with a degree of three is called as a cubic polynomial. Such types of equations involving cubic polynomials were called as cubic equation.

I hope my answer is correct...

Answer 2

Step-by-step explanation:

GIVEN:

$(x - 1)^3 = 8 \\ now \\ x - 1 = \sqrt[3]{8} \\ x - 1 = 2 \\ x = 2 + 1 \\ x = 3$

$then \\ (x + 1)^{2} \\ put \: the \: value \: of \: x \: \\ which \: you \: get \: in \: above \: euation \\ (3 + 1)^{2} \\ = (3)^{2} + 2(3)(1) + (1)^{2} \\ = 9 + 6 + 1 \\ = 16 \: ans$