if (x-1)³=8 then the value of (x+1)² is
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1
Answer:
The value of [x+1]^{2}[x+1]
2
is 16
Given:
[x-1]^{3}=8[x−1]
3
=8
To find:
[x+1]^{2}[x+1]
2
Solution:
To find the value of x,
[x-1]^{3}=8[x−1]
3
=8
[x-1]=(8)^{\frac{1}{3}}[x−1]=(8)
3
1
[x-1]=2[x−1]=2
x=3x=3
Then, [x+1]^{2}[x+1]
2
is,
[x+1]=3+1[x+1]=3+1
[x+1]=4[x+1]=4
[x+1]^{2} \Rightarrow 4^{2}[x+1]
2
⇒4
2
[x+1]^{2}=16[x+1]
2
=16
Any polynomial with a degree of two is called as a quadratic polynomial. Such types of equations involving quadratic polynomials were called as quadratic equations.
Similarly, a polynomial with a degree of three is called as a cubic polynomial. Such types of equations involving cubic polynomials were called as cubic equation.
I hope my answer is correct...
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