if x=1.3 bar and y=0.6 bar then x^2+y^2-2xy
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We see that I h1΄(x) I < 1 in interval (1,2) containing the root for all values of x. We use ... Solve ln x = 1.3 by inverse Interpolation using x= G(y) with G(1)=2.718 ,G( 1.5)= 4.481 , G(2)= ... p = (y - y0)/h = (1.3 - 1)/0.5 = 0.6.
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