Math, asked by momo2000, 1 month ago

if x+1/√3 is a root of x2+(√3-√2) -1= 0 then the value of P2+1 is

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Answered by sakshikotabagi

Answer:

The quadratic formula helps us solve any quadratic equation. First, we bring the equation to the form ax²+bx+c=0, where a, b, and c are coefficients. Then, we plug these coefficients in the formula: (-b±√(b²-4ac))/(2a) .

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if x+1/√3 is a root of x2+(√3-√2) -1= 0 then the value of P2+1 is​

Answers

if x+1/√3 is a root of x2+(√3-√2) -1= 0 then the value of P2+1 is