If x= -1/3 is a zero of a polynomial. p ( x) = 27x³-ax²-x+3 then find the value of a.
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x = -⅓ is a zero of the polynomial.
Put x = -⅓ to find value of a
p(x) = 27x³-ax²-x+3
p(x) =(3x)³-ax²-x+3
p(-⅓) = {3(-⅓)}³-a(-⅓)²-(-⅓)+3 = 0
(-1)³-a(1/9)+⅓+3 = 0
-1 - a/9+1/3+3 = 0
-a/9+1/3+2 = 0
(-a+3+18)/2 = 0
-a+3+18 = 0
a = 3+18
a = 21
Hope it helps
Put x = -⅓ to find value of a
p(x) = 27x³-ax²-x+3
p(x) =(3x)³-ax²-x+3
p(-⅓) = {3(-⅓)}³-a(-⅓)²-(-⅓)+3 = 0
(-1)³-a(1/9)+⅓+3 = 0
-1 - a/9+1/3+3 = 0
-a/9+1/3+2 = 0
(-a+3+18)/2 = 0
-a+3+18 = 0
a = 3+18
a = 21
Hope it helps
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