Question

if x = -1/3 is a zero of polynomial p(x)= 27x^3 - ax^2 - x + 3 , then find the value of 'a'.

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Answer 1

Answer = 3/7

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Answer 2

Answer:

21

Step-by-step explanation:

Given polynomial is

$p(x) = 27 {x}^{3} - a {x}^{2} - x + 3$

Substituting x = -1/3, we get,

$p( \frac{ - 1}{3} ) = 27 {( \frac{ - 1}{3} )}^{3} - a {( \frac{ - 1}{3} )}^{2} + \frac{1}{3} + 3 = 0$

$- 1 - \frac{a}{9} + \frac{10}{3} = 0$

$\frac{a}{9} = \frac{10}{3} - 1$

$\frac{a}{9} = \frac{7}{3}$

$a = 3 \times 7$

$a = 21$

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