Question

If x=-1/3 is a zero of polynomial p(x)=27x³-ax²-x+3, then find value of a.

Answer 1

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Answer 2

Hi friend!!

Given, If x=-1/3 is a zero of polynomial p(x)=27x³-ax²-x+3

Then, p(-1/3)=0

→27(-1/3)³-a(-1/3)²-(-1/3)+3=0

27(-1/27)-a(1/9)+1/3+3=0

-1-(a/9)+(10/3)=0

a/9=7/3

a=21

I hope this will help u ;)