If x=-1/3 is a zero of polynomial p(x)=27x³-ax²-x+3, then find value of a.
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Hi friend!!
Given, If x=-1/3 is a zero of polynomial p(x)=27x³-ax²-x+3
Then, p(-1/3)=0
→27(-1/3)³-a(-1/3)²-(-1/3)+3=0
27(-1/27)-a(1/9)+1/3+3=0
-1-(a/9)+(10/3)=0
a/9=7/3
a=21
I hope this will help u ;)
Given, If x=-1/3 is a zero of polynomial p(x)=27x³-ax²-x+3
Then, p(-1/3)=0
→27(-1/3)³-a(-1/3)²-(-1/3)+3=0
27(-1/27)-a(1/9)+1/3+3=0
-1-(a/9)+(10/3)=0
a/9=7/3
a=21
I hope this will help u ;)
ankitajena3739:
but ans is 7
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