Question

If x=-1/3 is a zero of the polynomial p(x)=27x^3-ax^2-x+3, find the value of 'a'. ​

Answer 1

Answer:

Just put value of x in equation

Step-by-step explanation:

Answer 2

Answer:

a = 21

Step-by-step explanation:

27(-1/3)^3 - (a)(-1/3)^2 -(-1/3) + 3 = 0

-1 - 1/9a + 1/3 + 3 = 0

2 + 1/3 - 1/9a = 0

7/3 -1/9a = 0

7*9 = 3a

63= 3a

therefore, a= 21