Question

If x=-1\3 is a zero of the polynomial p(x) =27x cube - ax square - x+3 then find the value of a

Answer 1

Hey there !!!!

p(x)= 27x³-ax²-x+3

x= -1/3 is a zero of polynomial of p(x)

So p(-1/3)=0

p(x)= 27x³-ax²-x+3

p(-1/3) =27*(-1/3)³-a(-1/3)²-(-1/3)+3 = 0

           3³ = 27 3² =9

p(-1/3) =  -27/27-a/9+1/3+3=0

             -1-a/9+3+1/3=0

               4+1/3=a/9

                13/3=a/9

                13*9/3=a

                  13*3 = 39 =a

So at a=39 x=-1/3 is a zero of polynomial of p(x)= 27x³-ax²-x+3.

Hope this helped you.........

Answer 2

Answer:

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