Question

If x = 1/3 is a zero of the Polynomial p(x) = 27x3 - ax2 - x + 3 then find the value of ‘a’ 3

Answer 1

Answer:

p(x)=27x3-ax2-x+3

p(1/3)=27*1/3*3-a*1/3*2-1/3+3=0

=27-2/3a+8/3=0

=89/3-2/3a=0

=89-2a/3=0

=89-2a=0

=-2a=-89

=a=89/2

therefore 'a' 3=267/2