If x = 1/3 is a zero of the Polynomial p(x) = 27x3 - ax2 - x + 3then find the value of ‘a’ 3
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Answer:
a = 33
Step-by-step explanation:
p(x) = 27x³ - ax² - x + 3
x = 1/3 is a zero of p(x)
then , p(x) = 0
put x = 1/3 in p(x)
p(1/3) = 27(1/3)³ - a(1/3)² - 1/3 + 3
= 27(1/27) - a(1/9) - 1/3 + 3
= 1 - a/9 - 1/3 + 3
= (3 - 1 + 9)/3 - a/9
= (2 + 9)/3 - a/9
= 11/3 - a/9 = 0
= 11/3 = a/9
= 11/3 × 9 = a
= 11 × 3 = a
= 33 = a
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