Question

If x= −1/3 is a zero of the polynomial p(x) = 27x³ − ax³ − x − 3 , then find the value of  a.​

Answer 1

Answer:

−9

Step-by-step explanation:

given,

p[x]) = 27x³ − ax³ − x − 3

g[x]= −1/3

zero of the polynomial g[x]is x −1/3=0

x=1/3

substitute x value in p[x]

p[x]=0

0=27[ −1/3]^2 − a[ −1/3]^2 − 1/3 − 3

0=27[1/9] − a[1/9] −1/3-3

0=3 − a/9 − 1/3 − 3

LCM=9

0=27 − a − 9 − 27

0= −a −9

a= −9