Question

If x=1/√3 is the root of kx^2+(√3-√2)x-1=0, then k is equal to:


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Answer 1

Answer:

ANSWER

kx

2

−3x−1=0

One root =

2

1

a=k,b=−3,c=−1

Sum of roots =

a

−b

Let the other root be x

x+

2

1

=

k

3

(2x+1)k=6

2xk+k=6.......(1)

Product of roots =

a

c

x×

2

1

=

k

−1

xk=−2.......(2)

Solving eq. (1) and (2)

2xk+k=6

2xk =−4

− +

_________

k=10