Math, asked by tejaswinimogal11, 4 months ago

If x=−1/3 is the root of the equation 3x2−(p+2)x−4=0, find the value of p.

Answers

Answered by mathdude500
4

Answer:

★Question★

  • If x = −1/3 is the root of the equation 3x² − (p + 2)x − 4 = 0, find the value of p.

★Given :-

  • x = −1/3 is the root of the equation 3x² − (p + 2)x − 4 = 0.

To Find :-

  • The value of p.

Solution:-

x = −1/3 is the root of the equation 3x² − (p + 2)x − 4 = 0

\bf\implies \:3 {( - \dfrac{1}{3} )}^{2}  - (p + 2)( - \dfrac{1}{3} ) - 4 = 0

\bf\implies \:3 \times \dfrac{1}{9}  + \dfrac{1}{3} (p + 2) - 4 = 0

\bf\implies \:\dfrac{1}{3} +  \dfrac{1}{3} (p + 2) - 4 = 0

\bf\implies \:\dfrac{1 + p + 2  - 12}{3}  = 0

\bf\implies \:p - 9 = 0

\bf\implies \:p = 9

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