Math, asked by riyachanne07, 6 months ago

If x= -1/3 is zero of polynomial p(x)= ax^3-x^2+x+4.. then find the value of a​

Answers

Answered by Anonymous
0

Step-by-step explanation:

a( -  \frac{1}{3} ) {}^{3 }  - ( -  \frac{1}{3}  )  {}^{2}  -  \frac{1}{3 }  + 4 = 0

    \frac{ - a}{27 }  -   \frac{1 }{9 }  = \frac{11}{3}

a=-3-99=-102

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