Math, asked by Abhash01, 7 months ago

if x=1/3-root8, find the value of x^3-2^2-7x+5​

Answers

Answered by sh1979
1

Answer:

8.48

Step-by-step explanation:

x=1/3-√8

ATQ

x^3-2^2-7x+5​\\(\frac{1}{3}-\sqrt{8})^3(-2)^2-7(\frac{1}{3}-\sqrt{8})+5\\(\frac{1}{27}-\sqrt{512})+4-\frac{7}{3}+\sqrt{56}+5\\\\\frac{1}{27}-22.6+4-\frac{7}{3}+7.4+5\\

\frac{1-610.2}{27}  +\frac{12-7+22.2+15}{3}\\\\\frac{-609.2}{27}+\frac{42.2}{3} \\ \\\frac{-609.2+379.8}{27} \\\\\frac{-229.2}{27}

Answer=8.48

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