Question

if (x+1/3,y/3-1) = (1/3,3/2) find x and y​

Answer 1

Answer:

X=0,y=3

Step-by-step explanation:

x+1/3=1/3

X=0

y/3-1=3/2

y/2=3/2

now y =3

Answer 2

The value of x is 0 and the value of y is 15/2.

Step-by-step explanation:

Consider the given equation is

$(x+\dfrac{1}{3},\dfrac{y}{3}-1)=(\dfrac{1}{3},\dfrac{3}{2})$

We need to find the value of x and y.

On comparing both sides we get

$x+\dfrac{1}{3}=\dfrac{1}{3}$

Subtract 1/3 from both sides.

$x=0$

$\dfrac{y}{3}-1=\dfrac{3}{2}$

$\dfrac{y}{3}=\dfrac{3}{2}+1$

$\dfrac{y}{3}=\dfrac{3+2}{2}$

Multiply both sides by 3.

$y=\dfrac{15}{2}$

Therefore, the value of x is 0 and the value of y is 15/2.

#Learn more

{x+1/3,y/3-1}=(1/3,3/2), find X and y​

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