if x(1+3i)+y(2-i)-5+i³=0 find x+y
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Answer:
x + y = 3
Step by step solution:
We are given that
x( 1 + 3i ) + y( 2 - i ) - 5 + i³ = 0
⇒ x + 3xi + 2y - yi - 5 - i = 0 ∵ i³ = i²·i = -i
⇒ ( x + 2y - 5) + ( 3x - y - 1)i = 0 + 0i
By equating real and imaginary parts, we get
x + 2y - 5 = 0 .............(1)
3x - y - 1 = 0 .........(2)
Multiplying equation (2) by 2 we get
6x - 2y - 2 = 0 ..........(3)
Adding equation (1) and equation (3) we get
7x = 7
⇒ x = 1
By putting x = 1 in equation (1) we get
1 + 2y = 5
⇒ 2y = 4
⇒ y = 2
And
x + y = 1 + 2 = 3
Thus
x + y = 3
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