Question

if (x-1/8)=8,find the value of (x²+1/x²) and (x⁴+1/x⁴)​

Answer 1

Answer:

$x^{2} +\frac{1}{x^2} =66$   and  $x^4 + \frac{1}{x^4} = 4354$

Step-by-step explanation:

       $x-\frac{1}{x}=8 \\\\(x-\frac{1}{x}) ^{2}= 8^{2} =64\\\\x^{2} +\frac{1}{x^2} -2 =64\\\\x^{2} +\frac{1}{x^2} =66$

..................................................

      $x^2 + \frac{1}{x^2}=66\\\\(x^2 + \frac{1}{x^2})^2=66^2 =4356\\\\x^4 +\frac{1}{x^4} + 2 = 4356\\\\x^4 + \frac{1}{x^4} = 4354$

(i think you have written the question wrong)