Question

if x=(1+a)/(1-a) and y=(1-a)/(1+a) then find x^2 +y^2 +xy

Answer 1

Answer:

Step-by-step explanation:

Given :

             $x=\frac{1+a}{1-a}$

            $x^{2}=\frac{(1+a)^{2} }{(1-a)^{2} }$--------------> Equation 1          (Squaring both sides)

            $y=\frac{1-a}{1+a}$

           $y^2=\frac{(1-a)^2}{(1+a)^2}$---------------> Equation 2        (Squaring both sides)

          $xy=\frac{(1+a)}{(1-a)} * \frac{(1-a)}{(1+a)}$

         xy = 1 ----------------> Equation 2                  (After cancelling terms)

Given equation is;

          x² + y² + xy ---------------> Equation 4

        Substituting Equation 1 , 2 and 3 in Equation 4 we get ;

       $=\frac{(1+a)^{2} }{(1-a)^{2} }+\frac{(1-a)^2}{(1+a)^2}+1$

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Answer 2

Answer:

0

Step-by-step explanation:

(1+a/1-a)^2+(1-a/1+a)+(1+a/1-a×1-a/1+a)

1a^2/a^2+a^2/1a^2