Question

if (x+1) and (x-1) are factors of Px³+x²-2x+9 then value of p and q are​

Answer 1

Answer:

Hey mate please write the correct question

Step-by-step explanation:

so your solution is in attachment

Answer 2

Answer:

p = 2

q = -1

Step-by-step explanation:

Let p(x) = px³ + x² - 2x + q

Since (x+1) and (x-1) are factors, (-1) and 1 are zeros according to factor theorem.

p(-1) = p(-1)³ + (-1)² - 2(-1) + q = -p + 1 + 2 + q = -p + 3 + q = 0

p(1) = p(1)³ + (1)² - 2(1) + q = p + 1 - 2 + q = p - 1 + q = 0

-p + 3 + q = p - 1 + q

3 + 1 = p + p + q - q

4 = 2p

∴p = 4/2 = 2

p(-1) = -p + 3 + q = 0

-2 + 3 + q = 0

1 + q = 0

∴q = -1

(OR)

p(1) = p - 1 + q = 0

2 - 1 + q = 0

1 + q = 0

∴q = -1

∴ Values of p and q are 2 and -1 respectively.

Hope this helps!!

Please mark as brainliest