if (x+1) and (x-1) are factors of x^3+2x^2+ax+b find a and b
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Let p(x) = ax3 + x2 - 2x + b
Since (x+1) and (x-1) are the factors of p(x),
∴ p(-1) = 0 and p(1) = 0
∴ p(-1) = a(-1)3 + (-1)2 - 2 (-1) + b = 0
⇒ - a + 1 + 2 + b = 0
⇒ a - b = 3 ---- (i)
Again, p(1) = a(1)3 + (1)2 - 2(1) + b = 0
⇒ a + 1 - 2 + b = 0
⇒ a + b = 1 ----- (ii)
solving equations (i) and (ii) we get a = 2 and b = -1
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