if (x+1) and (x-1) are the factors of ax³+x²-2x+b=0 then find a and b
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Answer:
Step-by-step explanation:
x = -1 (x+1)
a (-1)^3 + (-1)^2 -2(-1) + b = 0
-a +1 +2 +b = 0
b - a = -3
a-b = 3
x = 1 (x-1)
a (1)^3 + (1)^2 -2(1) + b = 0
a + 1 - 2 + b = 0
a+b = 1
by both equation
a-b = 3
a+b = 1
add both
2a = 4
a =2
b= -1
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